Prove that the bisector of an angle of a tringle divides the side opposite to the angle in ratio of the remaining sides
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Answer:
Step-by-step explanation:
TO PROVE:
AC/AB = DC/DB
CONSTRUCT A LINE PARALLEL TO AD and ray CA TO INTERSECT AT E
<CAD = <DAB--bisected angle
<CAD = <AEB--corresp angles
<DAB = <ABE--alternative angles
therfore,, TRIangle AEB is is0sceles and AE=AB
By side splitting theorem :
we get AC/AE=DC/BD
since AE = AB we have AC/AB = DC/DB..
HENCE PROOF........
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