Prove that the bisector of an angle the side opposite to the congle in the ratio of the remaining sides.
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Proof : Line CE∥ Line DA (Construction) and line BE is the transversal
∠BAD=∠AEC [Corresponding angles] ....(1)
AD∥EC
△AC is transversal
∴∠DAC=∠ACE [Alternative angles] ...(2)
But ∠BAD=∠DAC [Given] ...(3)
△∠AEC=∠ACE [from (1),(2) and (3)]
In △AEC side AC=side AE [Isosceles theorem] ...(4)$
Now in △BCE,segAD∥segCE
DC
BD
=
AE
AB
∴
DC
BD
=
AC
AB
Hence in a triangle, the angle bisector divides the side opposite to the angle in the ratio of the remaining sides.
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