Math, asked by 9377967770v, 3 months ago

Prove that the bisector of the angles of a parallelogram enclose a rectangle.​

Answers

Answered by anu18256
1

Step-by-step explanation:

As x+y=180

o

2

x

+

2

y

=90

o

⇒∠DPA=90

o

=∠SPQ (vertically opp)

∠SRQ=90

o

=∠PSR=∠PQR

Also In △ASB

y

&

B

are distinction ∴ As is d if from BS

hence PQRS is A rectangle.

solution

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