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Prove that the bisector of the vertical angle of an isosceles triangle bisects the base at right angle..
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pls answer...
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it's simple
clearly angleBAD=angle DAC
AD=AD(common)
AB=AC
so triangleABD=Triangle ADC
so angle ADB=anglleADC
angle(ADB+ADC)=180
2angle ADB=180
angle ADB=90
also both triangle are congruent
so BD=DC
hence AD is pependicular bisector
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