Question

prove that the bisector of the vertical angle of an isosceles triangle bisect the base at right angle​

Answer 1

Answer:

Step-by-step explanation:

in triangle ABD &ACD

AB=AC (GIVEN)

∠DAB=∠DAC (GIVEN)

∠B=∠C (ANGLES OPP TO EQUAL SIDE ARE EQUAL)

triangle ABD≅ACD (by ASA)

BD=CD(by CPCT)

                       ......(i)

∠ADB=∠ADC (by CPCT)

                                 ......(ii)

∠ADB+∠ADC=180 (linear pair)

∠ADB=∠ADB=180(from i)

2∠ADB=180

∠ADB=90

           .......(iii)

From i & iii

This is prove that bisector of the vertical angle of an isosceles triangle bisect the base at right angle​