Prove that the. bisector of two adjacent supplimentary angle are at right angle
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To prove that the bisectors of two adjacent supplementary angles include a right angle we draw the supplementary angles and also construct the angle bisectors of both the angles. ... OD is the angle bisector of angle ∠AOC and OE is the angle bisector of ∠BOC .
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- CE−→−CE→ is the bisector of ∠ACD and CF−→−CF→ is the bisector of ∠BCD
- ∠ECF = 90o
From the figure we know that
∠ACD and ∠BCD form a linear pair of angles
So we can write it as
- ∠ACD + ∠BCD = 180o
We can also write it as
- ∠ACE + ∠ECD + ∠DCF + ∠FCB = 180o
From the figure we also know that
- ∠ACE = ∠ECD and ∠DCF = ∠FCB
So it can be written as
- ∠ECD + ∠ECD + ∠DCF + ∠DCF = 180o
On further calculation we get
- 2 ∠ECD + 2 ∠DCF = 180o
Taking out 2 as common we get
- 2 (∠ECD + ∠DCF) = 180o
By division we get
- (∠ECD + ∠DCF) = 180/2
- ∠ECD + ∠DCF = 90o
Therefore, it is proved that ∠ECF = 90o
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