prove that the bisectors of base angles of an isoceles triangle are equal
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Step-by-step explanation:
In ΔABC,
AB = AC ....[ Given ]
∴ ∠C = ∠B ......(i) [ Angles opp. to equal sides are equal]
⇒
12∠C=12 ∠B
⇒ ∠BCF = ∠CBE ...(ii)
In ΔBCE and ΔCBF,
∠C = ∠B ...[ From (i) ]
∠BCF = ∠CBE ...[ From (ii) ]
BC = BC ...[ Common ]
∴ ΔBCE ≅ ΔCBF ...[ AAS ]
⇒ BE = CF ...[ c. p.c.t ]
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