Question

prove that the bisectorsof angles of the paralleogram form a rectangle​

Answer 1

Step-by-step explanation:

given : (1)paralleogram ABCD and O is intersecting point

(2)angle bisect each other

OA=OC

OD=OB

To prove : rectangle for that we need one angle 90°

proof:now, in ∆ADC&∆BCD

oa=oc (given )

ob=od (given)

if ADllBC and DC is a transversal ( because it is a parallelogram so pair of opposite is equal as well as parallel ).

so, angle D +angle C =180(co-interior angle )

90+90=180

so,∆ADC≈∆BCD

hence , we just need to prove one angle 90° and then all become 90°as well ( this is the property of rectangle)

hence , proved