Prove that the bisectots of opposite angles of a parrelogram are parallel
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Step-by-step explanation:
Here, PQRS is a parallelogram and line segment PX,RY bisect angles P and R respectively.
We have to prove that PX∥RY
We know that, in parallelogram opposite angles are equal.
∴ ∠P=∠R
⇒
2
1
∠P=
2
1
∠R
⇒ ∠1=∠2 ---- ( 1 ) [ Since, PX and RY are bisectors of ∠P and ∠R respectively ]
Now, PQ∥RS and the transversal RY intersects them.
∴ ∠2=∠3 ---- ( 2 ) [ Alternate angles ]
From ( 1 ) and ( 2 ) we get,
⇒ ∠1=∠3
Thus, transversal PQ intersects PX and YR at P and Y such that ∠1=∠3 i.e. corresponding angles are equal.
∴ PX∥RY
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