Question

Prove that the centres of the three circles x2 + y2 - 4x - 6y - 12 = 0,
x2+y2 + 2x + 4y - 10 = 0 and x2 + y2 - 10x – 16y-1 = 0 are collinear.
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Answer 1

hence, Prove that the centres of the three circles x2 + y2 - 4x - 6y - 12 = 0,

x2+y2 + 2x + 4y - 10 = 0 and x2 + y2 - 10x – 16y-1 = 0 are collinear.