Question

Prove that the circle drawn on any equal side of an isosceles triangle as diameter bisect the third side

Be fast....answer the question...plss

Answer 1

let the triangle be ABC
with AB=AC
and Aob is a diameter of the circle with o as the centre
p is the point where the circle touches the side bc of triangle abc.
Then join ap.
angle APB=90 (angle substended by diameter)
also in an isosceles triangle the perpendicular drawn from the vertex containing the equal sides bisects the 3rd side.
There fore BP=CP