Question

prove that the circle drawn with any side of rhombus as diameter passes through the point of intersection of its diagonal​

Answer 1

Answer:

the following sentences:

(a) The social democracy means [a way of life which recognises liberty, equality and fraternity]

(b) Fraternity means [a sense of common brotherhood of all Indians.]

(c) The politically minded Indians preferred the expression [the Indian nation'.]

Answer 2

Answer: Let ABCD be a rhombus in which diagonals intersect at point O, and a circle is drawn by taking side CD as its diameter. We know that a diameter subtends 90° on the arc.

Therefore, ∠COD = 90°

Also, in the rhombus, the diagonals intersect each other at 90°.

∠AOB = ∠BOC = ∠COD = ∠DOA = 90°

But ∠COD is 90° and this can only happen on a semicircle with diameter DC since the angle subtended by the diameter on a semicircle is 90°.

Clearly, point O has to lie on the circle.

Thus, the circle passes through the point of intersection of its diagonals O.

Step-by-step explanation: