Question

prove that the circle drawn with the any side of rhombus as diameter passing through the point of intersection of diagonals

Answer 1

Let ABCD be the rhombus in which diagonals bisect at O and circle is drawn  taking side CD as it's diameter 
< COD = 90 degree       - diameter subtends 90 de on the arc

also in rhombus the diagonals bisect at 90 degree.

so <AOB = <BOC= <COD = <DOA = 90

Clearly the point O has to lie on the circle
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hope it helps!

Answer 2

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