Prove that the derivative of Ln(x) = 1/x from the definition of implicit differentiation.
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y = lnx
x = e^y
The derivative of x with respect to y is just e^y
Then the derivative of y with respect to x is equal to 1/(e^y)
As y = lnx,
1/(e^y) = 1/(e^lnx) = 1/x
Explanation:
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