Prove that the diagnols of a square are equal and bisect each other at right angles.
1) AC=BD
2) OA=OC AND OB=OD 3) AC IS PERPENDICULAR TO BD
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let ABCD be a parallelogram
sum of interior angle of a parallelogram in a same line or you can say parallel to each other and in that case the sum of interior angle is 180 degree so angle A and angle b is equal to 180 degree
similarly we will take angle C and Angle B there some also will be 180 degree and we have already said that angle b is 90 degree so the c will also be 90 degree
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