Prove that the diagonal elements of a skew symmetric matrix are all zeros.
Answers
Answer:
Step-by-step explanation:
Proof:
Let A=[aij]n×n be a skew symmetric matrix.
⇒aij=−aji for all i & j.
⇒aii=−aii (Putj=i)
⇒2aii=0⇒aii=0.
Thus in a skew symmetric matrix all elements along the principal diagonal are zero.
We have a square matrix , say M which is also a skew symmetric matrix
Now we have to prove that , diagonal elements of a skew symmetric matrix are always zero.
.) Let mij be the elements of the matrix M , where i is donating rows and j is donating column.
Now , matrix M is a skew symmetric matrix
⇒ mij = −mji for all i & j.
⇒ mij + mji = 0
.) Now condition for diagonal elements is i = j , hence mii or mjj represents the diagonal elements
=> mii + mii = 0
=> 2*mii = 0
=> mii = 0 = mjj
Hence every diagonal element is zero
Thus, in a skew symmetric matrix , all elements along the diagonal are zero.