Prove that the diagonal elements of an skewsymmetric matrix are zero
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A)
Toolbox:
A square matrix A=[aijij] is said to be skew symmetric if A'=-A that is [aij]=−[aji][aij]=−[aji] for all possible value of i and j.
To prove:
All diagonal elements of a skew-symmetric matrix are all zero.
Proof:
Let A=[aij]n×nA=[aij]n×n be a skew symmetric matrix.
⇒aij=−aji⇒aij=−aji for all i & j.
⇒aii=−aii⇒aii=−aii (Putj=i)(Putj=i)
⇒2aii=0⇒aii=0.⇒2aii=0⇒aii=0.
Thus in a skew symmetric matrix all elements along the principal diagonal are zero...
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in a skew symmetric matrix
aij=−aji
if elements are in diagonal then,
i=j
aii=−aii
2aii=0.
aii=0.
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