Question

prove that the diagonal of a square divide into four congruent triangles​

Answer 1

Step-by-step explanation:

let the square be abcd.

let the point of intersection be o.

so, triangles are aob,aod,boc,doc.

considering aob and doc,

ao=do(half the diognals)

oc=ob(half the diognals)

ang aob=doe(opposite angles are equal)

so,aob is con to doc

in aod and doc

do=do(common)

dc=ad(sides of square)

aod=doc(90 deg)

so,aod is con to doc

so,aob=aod=boc=doc.

Answer 2

Answer:

aod =boc =doc=aob

Step-by-step explanation:

it is your Ans

stap by step explanation

OK

thanks ❤