Question

prove that the diagonal of parallelogram bisect each other​

Answer 1

$\huge\sf \orange{hello}...$

Let consider a parallelogram ABCD in which AB||CD and AD||BC.

In ∆AOB and ∆COD , we have

∠DCO=∠OAB (ALTERNATE ANGLE)

∠CDO= ∠OBA. (ALTERNATE ANGLE)

AB=CD. (OPPOSITE SIDES OF ||gram)

therefore , ∆ AOB ≅ ∆COD. (ASA congruency)

hence , AO=OC and BO= OD. (C.P.C.T)

Answer 2

In a parallegrom, first make two diagonals  u will get two triangles. Take two triangles in such a way that their base is common and they have their diagonals. We know that the opp. Sides are equal and parallel so angles shall be also equal by alternate angles. Prove that the triqngles are congruent and by cpctc the diagonals will be q

Equal.