Question

prove that the diagonal of rhombus divides it into two pairs of congruent triangles

Answer 1

To proof = a diagonal of a rhombus divides it into two equal or congruent triangles. ..

proof =
let us take two triangles which are formed by dividing the rhombus. .
let those triangles be ABC and ACD ..

now in triangles ABC and ACD we have ,,,,

AC= AC ( common )
AB= CD( AS we know that opposite side of a rhombus are equal )
AD =BC ( opposite side of a rhombus are always equal )

therefore, ,, by SSS criteria both the triangles are congruent. ..

theirfore,,, if both the triangles are congruent then it means that a diagonal of a rhombus divides two congruent triangles ...

if my answer helps you then mark my answer as brainliest ....

Answer 2

Step-by-step explanation:

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