prove that the diagonal of square are equal and bisect each other at right angles.
Answers
Answered by
1
its answer of your question
Attachments:
abhisheksp:
As Brainly says "Remember that it's against our guidelines to copy content from other websites, books or any other material to which you don't own the rights to. We know you have the power to solve these problems on your own!" and ur coping the solution from Books Its not ur answer , its not ur ideas
Answered by
2
Given : Let the ABCD be a rhombus. AC and BD are 2 diagonals.
To Prove: AO=OC, BO=OD.(i)
Angle AOD = angle AOB = 90° is AC perpendicular to BD ( ii)
Proof : In triangle AOD and triangle BOC
AD = BC ( opposite side of the rhombus)
angle ADO = CBO ( alternate angle ad AD parallel to BC, BD transversal)
angle AOD= angle BOC ( vertically opposite angle)
Hence triangle AOD is congruent to triangle BOC by AAS property
And AO = OC and BO = OD by cpct [ proved (i)]
After this see the attachment
To Prove: AO=OC, BO=OD.(i)
Angle AOD = angle AOB = 90° is AC perpendicular to BD ( ii)
Proof : In triangle AOD and triangle BOC
AD = BC ( opposite side of the rhombus)
angle ADO = CBO ( alternate angle ad AD parallel to BC, BD transversal)
angle AOD= angle BOC ( vertically opposite angle)
Hence triangle AOD is congruent to triangle BOC by AAS property
And AO = OC and BO = OD by cpct [ proved (i)]
After this see the attachment
Attachments:
Similar questions