prove that the diagonals of a parllelogram bisect each other
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ABCD is a parallelogram, diagonals AC and BD intersect at O.
In triangles AOD and COB,
DAO = BCO (alternate interior angles)
DAO = BCO (alternate interior angles)AD = CB.
DAO = BCO (alternate interior angles)AD = CB.ADO = CBO (alternate interior angles)
DAO = BCO (alternate interior angles)AD = CB.ADO = CBO (alternate interior angles)AOD COB (ASA)
Hence, AO = CO and OD = OB (c.p.c.t)
Thus, the diagonals of a parallelogram bisect each other.
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