Question

. Prove that the diagonals of a rectangle are of equal length.
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Answer 1

Step-by-step explanation:

Theorem

The diagonals of a rectangle are equal.

Proof

Let ABCD be a rectangle.

We prove that AC = BD.

In the triangles ABC and DCB:

BC = CB (common)

AB = DC (opposite sides of a parallelogram)

angle ABC =angle DCA = 90° (given)

so triangle ABC ≡ triangle DCB (SAS)

Hence AC = DB (c.s.c.t).

Answer 2

Answer:

Step-by-step explanation: