Prove that the diagonals of the parallelogram bisect each other. Take scale on both axes as 1cm = a units
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Answered by
10
Answer:
Step-by-step explanation:
Answered by
2
Answer:
Step-by-step explanation:
let a parallelogram ABCD where AB║CD and BC║AD
BD and AC cut each other at point E
to prove :- AE=EC and DE=EB
proof:-
in ΔAEB and ΔCED
∠CAB=∠DCA (alternate angle)
∠ABD=∠BDC (alternate angle)
AB=DC (opposite side are equal)
ΔAEB≅ΔCED (ASA)
AE=EC (CPCT)
BE=ED (CPCT)
hence proved.
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