prove that the difference of any two sides of a triangle is less than the third side
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Start with the Triangle Inequality Theorem which is, the sum of any two sides of a triangle must be greater than the third. Stated algebraically:
A < B + C
B < A + C
C < A + B
1. Subtract B from both sides, then A - B < C
2. Subtract C from both sides, then B - C < A
3. Subtract A from both sides, then C - A < B
A < B + C
B < A + C
C < A + B
1. Subtract B from both sides, then A - B < C
2. Subtract C from both sides, then B - C < A
3. Subtract A from both sides, then C - A < B
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