Question

prove that the direction of electric field intensity is awlays perpendicular to the equipotentail surface.​

Answer 1

Answer:

The electric field is always perpendicular to equipotential surface because E =− ∇V. As surfaces are equipotential so it must be spaced such that surfaces having equal differences in potential are separated by equal distances. As E=− dV/dr so it must have decreasing potentials in the direction of the field.

Answer 2

The electric field is always perpendicular to equipotential surface because E =− ∇V. As surfaces are equipotential so it must be spaced such that surfaces having equal differences in potential are separated by equal distances. As E=− dV/dr so it must have decreasing potentials in the direction of the field.

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