prove that the distance travelled by a body in nth second one s given by
snth=u+a/2(2n-1)
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Answer:
ANSWER
s
nth
=μ+
2
a
(2n−1)
The real formula is ;
μ(1)+
2
a
(1) (2n - 1 )
where 1 represent 1 sec as times
LHS = [ L ]
[ L ] = μ(1)=[LT
−1
][T]
= [ L ]
a
a
(1)[2n−1] = LT
−2
[ T ] [ T ]
= L
[ L ] = [ L ] + [ L ]
hence the formula is correct
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