Prove that the distance travelled during equal intervals of time by body falling from rest stand to one another in the same ratio as the odd numbers beginning with unity
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u = 0
in the first interval t :
=> v = 0 + gt = gt
h1 = 0 + 1/2 gt^2 = 1/2 gt^2 --- (1)
.. for the second interval t : => v2 = v + gt = gt + gt = 2gt
h2 = vt + 1/2 gt^2 = gt^2 + 1/2 gt^2 = 3/2 gt^2 --- (2)
.. for the 3rd interval t :=> v3 = v2 + gt = 2gt + gt = 3gt
=> h3 = v2t + 1/2 gt^2 = 2gt^2 + 1/2 gt^2 = 5/2 gt^2 --- (3)
and .. for the 4th interval t :
=> h4 = v3t + 1/2 gt^2 = 3gt^2 + 1/2 gt^2 = 7/2 gt^2 --- (4)
now if u find the ratio h1 : h2 : h3 : h4 u get :
1/2 gt^2 : 3/2 gt^2 : 5/2 gt^2 : 7/2 gt^2
by cancelling 1/2gt^2 u get the ratio :
1 : 3 : 5 : 7
hope it's clear
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