Physics, asked by hkousik243, 8 months ago

Prove that the energy density stored in an electric field is

1
/2
epsilon not E^2


,where epsilon not is the permittivity of free space and E is the electric field

component.​

Answers

Answered by Anonymous
0

ANSWER

When a conductor is a charged, during the process of charging work has to be done to bring the charge on the surface of conductor. This work done is stored in the form of surrounding the conductor in the form of electrostatic energy per unit volume is called energy density.

Consider a charged conductor of surface charge density σ in a median of dielectric constant K. Consider small area ds of the conductor.

We know that the mechanical force per unit area of a charged conductor = 1/2£E^2

Mechanical force acting on area ds : 1/2£E^2ds

Assume that the element ds is displaced through a distance dl under the action of mechanical force acting on area ds. During the displacement the work done:

dw=1/2£E^2ds*dl

dw=1/2£E^2*dv (dv=ds*dl)

This work done is stored in the electric field in form of electrostatic energy and it is given by:

Electrostatic energy=1/2£E^2*dv

Energy per unit volume = Electrostatic energy per unit volume = du/dv =1/2£E^2

so, du/dv=1/2£°kE^2

This is the expression for energy density of the medium.

If the charged conductor is placed in air, k= 1.

∴ Energy density = 1/2£°E^2

£ = epsilon

£° = epsilon not

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