Science, asked by freefireacount4724, 6 months ago

prove that the energy remains constant in case of a freely falling body?with diagram......(100% guaranty of brainlist)​

Answers

Answered by akshank610
1

Answer:

Explanation:

Law of conservation of energy states that the energy can neither be created nor destroyed but can be transformed from one form to another.

Let us now prove that the above law holds good in the case of a freely falling body.

Let a body of mass 'm' placed at a height 'h' above the ground, start falling down from rest.

In this case we have to show that the total energy (potential energy + kinetic energy) of the body at A, B and C remains constant i.e, potential energy is completely transformed into kinetic energy.

At A,  

Potential energy = mgh

Kinetic energy = 1/2 mv² = 1/2 * m* 0Kinetic energy = 0 [the velocity is zero as the object is initially at rest]

\ Total energy at A = Potential energy + Kinetic energy

= mgh + 0  

Total energy at A = mgh       …(1)

At B,

Potential energy = mgh

= mg(h - x)            [Height from the ground is (h - x)]Potential energy = mgh - mgx

Kinetic energy = 1/2 mv²

The body covers the distance x with a velocity v. We make use of the third equation of motion to obtain velocity of the body.

v2 - u2 = 2aSHere, u = 0, a = g and S = x

v² - 0 = 2gx  

Here, u = 0, a = g and S = x

v² -  0 = 2gx  

v² = 2gx  

kinetic energy = 1/2 mv²

= 1/2 m2gx    

Kinetic energy = mgx

Total energy at B = Potential energy + Kinetic energy

= mgh - mgx + mgx

Total energy at B = mgh …(2)

At C,

Potential energy = m x g x 0 (h = 0)

Potential energy = 0Kinetic energy = 1/2 mv²

The distance covered by the body is hv2 - u2 = 2aS

Here, u = 0, a = g and S = h

v² - 0 = 2gh  

v² = 2gh  

kinetic energy = 1/2 mv²  

= 1/2 m * 2gh  

Kinetic energy = mgh

Total energy at C = Potential energy + Kinetic energy= 0 + mgh

Total energy at C = mgh …(3)It is clear from equations 1, 2 and 3 that the total energy of the body remains constant at every point. Thus, we conclude that law of conservation of energy holds good in the case of a freely falling body. i know its too big but this is anser make it short if u want!!!

Answered by khushaldube
0

Answer:

Let a body of mass 'm' placed at a height 'h' above the ground, start falling down from rest. In this case we have to show that the total energy (potential energy + kinetic energy) of the body at A, B and C remains constant i.e, potential energy is completely transformed into kinetic energy.

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