prove that the equal chords ab and CD of a circle subtend equal angles at the centre use the above to find angle abc in figure 4 where O is the centre of the circle
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The equal chords AB and CD of a circle subtend equal angles ∠AOB and ∠COD at the center of O of the circle.
- Given,
- AB and CD are the equal chords of a circle.
- O is the center of the circle.
- From given figure, consider,
- ΔAOB and ΔCOD
- we have,
- OA=OC
- OB=OD
- AB=CD
- From SSS theorem, we have,
- ΔAOB≅ΔCOD
- Hence, from congruence parts of congruent triangle, we get,
- ∠AOB=∠COD
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