prove that the equal chords of circle subtend equal angles at the centre. for class 9 maths
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Answer:
To Prove: AB = CD. Solution: AC and BD are diameters of a circle which intersect at the center O. We know that the angles subtended by the chords of a circle at the center are equal, then chords are equal. Thus, AB = CD.
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Given :
- A circle with center O.
- AB and CD are equal chords of a circle.
i.e. AB = CD
To Prove :
- ∠AOB = ∠DOC
Proof :
★ In △AOB & △DOC
- AO = OD (Radius)
- AB = CD (Given)
- OB = OC (Radius)
∴ △AOB ≅ △DOC (SSS rule)
∴ ∠AOB = ∠DOC (CPCT)
⎔ Hence Proved !
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