prove that the equation x²-15x+1=0 has atmost one real root on the interval [ -2,2]
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Use tge discriminant methid to find roots as there is no middle term splitting.
D = Bsquare-4ac
X= - b+/-root over D divided by 2a
D = Bsquare-4ac
X= - b+/-root over D divided by 2a
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