Math, asked by prasa162006, 9 months ago

.Prove that the equation x2(p2+q2) + 2x(pr+qs) + r2+ s2=0 has no real roots. If ps=qr,then
show that the roots are real and equal.
Anyone answer it please.

Answers

Answered by kumarsube9993
2

Answer:

Equation px

2

+2qx+r=0 and qx

2

−2

pr

x+q=0 have real roots, then

b

2

−4ac≥0 for both equations

From first

4q

2

−4pr≥0⇒q

2

≥pr ...............(1)

and from second

4(pr)−4q

2

≥0 (for real root)

⇒pr≥q

2

...............(2)

From (1) and (2), we get result q

2

=pr

Answered by praveen1436praveen
0

Answer:

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Step-by-step explanation:

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