prove that the equations 5x+3y+2z=12, 2x+4y+5z=2, 39x+43y+45z=c are incompatible unless c=74 and in that case the equation are satisfied by x=2+t, y=2-3t, z=-2+2t where, t is arbitrary quantity
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Answer:
3y = 452
=> y = 152
=>=y=1: 152
=> 2÷ y = 2÷ 15z
5x = 45z
=> x=92
=>1=r=1:9z ----
equl + equ2
-1
2
1:- 2 +2 : y=2 : 152 +1:9z
= 23 ÷ 452z
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