prove that the equilateral triangle described on the two sides of a right angle triangle are together equal to the equilateral triangle on the hypotenuse in terms of their area.
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Let the length of the perpendicular sides of the right angled triangle be a and b.
let the length of the hypotenuse be c.
the area of the equilateral triangle ABD described on the side AB with length a = √3/4a2
the area of the equilateral triangle BCE described on the side BC with length b = √3/4b2
sum of the areas of equilateral triangles described on the perpendicular sides
=√3/4a2+√3/4b2=√3/4.(a2+b2)=√3/4.c2 [by pythagoras theorem]
= area of the equilateral triangle ACF described on the hypotenuse AC
let the length of the hypotenuse be c.
the area of the equilateral triangle ABD described on the side AB with length a = √3/4a2
the area of the equilateral triangle BCE described on the side BC with length b = √3/4b2
sum of the areas of equilateral triangles described on the perpendicular sides
=√3/4a2+√3/4b2=√3/4.(a2+b2)=√3/4.c2 [by pythagoras theorem]
= area of the equilateral triangle ACF described on the hypotenuse AC
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thakursiddharth:
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Answer:here is ur answer
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