prove that the exterior angle of a regular decagon is one third the interior angle of a regular pentagon
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Hii mate ,
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A decagon has 10 sides and sum of the exterior angles of decagon = 3600
∵Decagon is regular
Measuer of each exterior angle = 36010=360−−−−−−−(i)
A pentagon has five sides and sum of interior angles of a pentagon
= (5−2)×1800=3×1800=5400
As pentagon is regular so measure of each angle of the pentagon
=54005=1080−−−−−(ii)
From (i) and (ii)
∴Measure of each exterior angle of a decagon=13Measure of each interior angle of a pentagon
Hence proved~~~~
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Hope it helps u !!!
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