Prove that the exterior angle of a regular Decagon is one-third the interior angle of a regular Pentagon
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the exterior angle of a decagon is equal to 360/10 = 36 degrees. the internal angle of a pentagon is equal to 180 - 360/5 which is equal to 180 - 72 degrees which is equal to 108 degrees. 3 * 36 is equal to 108 degrees. ... for the pentagon, the first formula will become 3 * 180 / 5 = 3 * 36 = 108.
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