prove that the exterior angle of a regular pentagon is twice the exterior angle of a regular decagon
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Answer:
Each exterior angle of polygon =360/n
Step-by-step explanation:
For a pentagon each exterior angle =360/5=72 degrees
For a decagon each exterior angle =360/10=36 degrees
exterior angle of pentagon / exterior angle of decagon=72/36=2
therefore,
exterior angle of Pentagon = 2 times the exterior angle of Decagon
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