Question

prove that the exterior angle of the equilateral triangle is twice to the interior angle​

Answer 1

Answer:

exterior angle of a polygon with n sides is 360/n

inside angle is 180(n-2)/n

so 360/n = 2(180)(n-2)/n

360 = 360n - 720

360n = 1080

n = 3 

looks like an equilateral triangle

check: inside angle = 60 degrees

exterior angle is 120 degrees

Answer 2

Answer:

exterior angle of a polygon with n sides is 360/n

inside angle is 180(n-2)/nso 360/n = 2(180)(n-2)/n

360 = 360n - 720

360n = 1080

n = 3