prove that the external bisector of an angle of a triangle divides the opposite side in the ratio of the other two sides
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Exterior angle bisector theorem : The external bisector of an angle of a triangle divides the opposite side externally in the ratio of the sides containing the angle. Given : A ΔABC, in which AD is the bisector of the exterior ∠A and intersects BC produced in D. Construction : Draw CE || DA meeting AB in E.
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