prove that the following are irrational 1/root2,7/root 5,6+root 2
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Answered by
7
Answer:
Step-by-step explanation:
1/√2=√2/2rationalisation)
Assume that √2/2 is rational
Therefore,√2/2=a/b where a and b are co primes and b not equal to 0
√2/2=a/b
√2=2a/b
Since a and b are intergers,2a/b would be a rational number. But √2 is irrational.
This shows that the assumption of √2/2 as rational is wrong
Therefore, √2/2 or 1/√2 is irrational.
Same way,7/√5 Is irrational.
6+√2 , when assumed as rational, 6+√2=a/b
√2=a/b-6
But √2 is irrational
Therefore 6+√2 is irrational
Answered by
10
Answer:
Hence 1/root2,7/root5, 6+ Root2 are irrational numbers
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