prove that the following are irrational 6+√2
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Step-by-step explanation:
Prove that 6 + √2 is an irrational number.
Answer:
Given 6 + √2
To prove: 6 + √2 is an irrational number.
Proof:
Let us assume that 6 + √2 is a rational number.
So it can be written in the form a/b
6 + √2 = a/b
Here a and b are coprime numbers and b ≠ 0
Solving
6 + √2 = a/b
we get,
=> √2 = a/b – 6
=> √2 = (a-6b)/b
=> √2 = (a-6b)/b
This shows (a-6b)/b is a rational number.
But we know that √2 is an irrational number, it is contradictsour to our assumption.
Our assumption 6 + √2 is a rational number is incorrect.
6 + √2 is an irrational number
Hence, proved
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