Prove that the following are irrational numbers
1) Root 3 + root 5
Plzzzzz explain I had exam tomorrow plzzz
Answers
Answered by
9
bonjour!
i am here to help u with this problem
Let √3 + √5 be a rational number , say r
then √3 + √5 = r
On squaring both sides,
(√3 + √5)2 = r2
3 + 2 √15 + 5 = r2
8 + 2 √15 = r2
2 √15 = r2 - 8
√15 = (r2 - 8) / 2
Now (r2 - 8) / 2 is a rational number and √15 is an irrational number .
Since a rational number cannot be equal to an irrational number . Our assumption that √3 + √5 is rational wrong .
hope it helps
hafsasanakhan67:
Is this ryt?
Answered by
26
# We have to prove that √3 + √5 is irrational.
→ Let us assume that √3 + √5 is rational number.
Now,
√3 + √5 = a/b
On squaring both sides we get,
3 + 5 + 2√15 = (a²/b²)
[As, (a + b)² = (a² + b² + 2ab)]
8 + 2√15 = (a²/b²)
2√15 = [(a² - 8b²) ÷ b²]
√15 = ½ [(a² - 8b²) ÷ b²]
Now, ½ [(a² - 8b²) ÷ b²] is a rational number
So, √15 is also a rational number.
But we know that √15 is irrational number.
So, our assumption is wrong √3 + √5 is a rational number.
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Or you can do it like this also.
→ Let us assume that √3 + √5 is a rational number.
So,
√3 + √5 = a
On, squaring both sides we get,
8 + 2√15 = a²
2√15 = a² - 8
√15 = [(a² - 8) ÷ 2]
Now, [(a² - 8) ÷ 2] is rational number.
So, √15 is also a rational number.
But we know that √15 is a irrational number.
So, √15 is also a irrational number.
So, our assumption is wrong.
√3 + √5 is a irrational number.
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