Prove that the following number is irrational:-
swatisinger:
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Answers
Answered by
1
hey friend here is your answer....
√7 is irrational because it value is 2.64575131 (approx)
which is a not terminating and non repeating....
that's why√7 is irrational...
hope it helps you dear friend...
if it helps mark as brainliest
√7 is irrational because it value is 2.64575131 (approx)
which is a not terminating and non repeating....
that's why√7 is irrational...
hope it helps you dear friend...
if it helps mark as brainliest
Answered by
2
prove that √7 is irrational
Let us assume √7 is rational
√7=p/q( where p and q are co- prime)
squaring on both sides
(√7)^2=p^2/q^2
7=p^2/q^2
7q^2=p^2
q^2=p^2/7
7 divides p and p^2 also
let p=7m
7q^2=(7m)^2
7q^2=49m
7q^2/49=m
q^2/7=m
7 divides q and q^2
our assumption is wrong
It is contradiction
Hence √7 is irrational
HENCE PROVED
Hope it helps
please mark me as brainliest
Let us assume √7 is rational
√7=p/q( where p and q are co- prime)
squaring on both sides
(√7)^2=p^2/q^2
7=p^2/q^2
7q^2=p^2
q^2=p^2/7
7 divides p and p^2 also
let p=7m
7q^2=(7m)^2
7q^2=49m
7q^2/49=m
q^2/7=m
7 divides q and q^2
our assumption is wrong
It is contradiction
Hence √7 is irrational
HENCE PROVED
Hope it helps
please mark me as brainliest
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