Question

prove that the following numbers are irrational 3 + √5​

Answer 1

Hey mate here is your answer....

Hope it help you... So, plzzzzz mate Mark my ans as brainliest answer....

Answer 2

Answer:

Step-by-step explanation:

→ Let us assume that 3 + √5 is a rational number.

→ Now,

→ 3 + √5 = (a ÷ b)

→ [Here a and b are co-prime numbers]

→ √5 = [(a ÷ b) - 3]

→ √5 = [(a - 3b) ÷ b]

→ Here, {(a - 3b) ÷ b} is a rational number.

→ But we know that √5 is a irrational number.

→ So, {(a - 3b) ÷ b} is also a irrational number.

→ So, our assumption is wrong.

→ 3 + √5 is a irrational number.

→ Hence, proved that 3+√5 is irrational.