Prove that the following numbers are irrational numbers
7√5.
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Answer:
7√5 is irrational number.
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Answered by
2
Answer:
Let us assume that 7√5 is rational number
Hence 7√5 can be written in the form of a/b where a,b(b
≠0) are co-prime
⟹ 7√5 = a/b
⟹ √5 = a/7b
But here √5 is irrational and a/7b is rational
as Irrational ≠ Rational
∴ 7√5 is an irrational number
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