Prove that the four point A, B, C and D are coplanar if and only if AD.(AB×AC)=0
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ABCD are coplanar if and only if AD~ = kAB~ + lAC~ for some k, l
if and only if d − a = k(b − a) + l(c − a)
if and only if a(k + l − 1) + b(−k) + c(−l) + d = 0
⇒ αa + βb + γc + δd = 0 and α + β + γ + δ = 0
Conversely if αa + βb + γc + δd = 0 and α + β + γ + δ = 0
If δ = 0
αa + βb + γc = 0 and α + β + γ = 0 So A, B, C are colinear
Thus ABCD are coplanar.
If δ 6= 0
α
δ
a +
β δ b + γ δ
c + d = 0
Let β
δ = −k
γ
δ = −l then α
δ = k + l − 1
Hence ABCD are coplanar.
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