Math, asked by banashreehazarika3, 8 months ago

Prove that the function f(x)=5x-3 is continous at x=0, at x=-3 and at x=5​

Answers

Answered by asbhadoria2004
1

Step-by-step explanation:

For X=0,

f(X)=5x-3

=5×0-3=-3

For X=-3,

f(X)=5x-3

=5×(-3)-3=-15-3=-18

For X=5,

f(X)=5x-3

=5×5-3=25-3=22

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