Prove that the function f(x)=5x-3 is continous at x=0, at x=-3 and at x=5
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Step-by-step explanation:
For X=0,
f(X)=5x-3
=5×0-3=-3
For X=-3,
f(X)=5x-3
=5×(-3)-3=-15-3=-18
For X=5,
f(X)=5x-3
=5×5-3=25-3=22
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