prove that the function is continues f(x)=5x-3
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The given function is f(x)=5x−3
At x=0,f(0)=5(0)−3=−3
x→3
lim
f(x)=
x→3
lim
f(5x−3)=5(0)−3=−3
∴
x→3
lim
f(x)=f(0)
Therefore, f is continuous at x=0
At x=−3,f(−3)=5(−3)−3=−18
x→−3
lim
f(x)=
x→−3
lim
(5x−3)=5(−3)−3=−18
∴
x→−3
lim
f(x)=f(−3)
Therefore, f is continuous at x=−3
At x=5,f(x)=f(5)=5(5)−3=25−3=22
x→5
lim
f(x)=
x→5
lim
(5x−3)=5(5)−3=22
∴
x→5
lim
f(x)=f(5)
Therefore, f is continuous at x=5.
Hence f is continuous at all the given points (In fact f is continuous for all R, Since it is a polynomial )
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